Line 22: Line 22:
 
</syntaxhighlight> This makes the content of the address pointed to by 'a' 5. But 'a' is not pointing to any valid address (int *a assigns garbage value to 'a') and hence this assignment can cause segmentation fault
 
</syntaxhighlight> This makes the content of the address pointed to by 'a' 5. But 'a' is not pointing to any valid address (int *a assigns garbage value to 'a') and hence this assignment can cause segmentation fault
  
 +
{{subst:wikEd}}
  
 +
{{Template:FB}}
  
  
<div class="fb-like"  data-layout="standard" data-action="like" data-show-faces="true" data-share="true"></div>
+
<disqus/>
  
 
<div class="fb-share-button"  data-type="button_count"></div>
 
<disqus/>
 
  
 
[[Category:Coding Questions]]
 
[[Category:Coding Questions]]

Revision as of 16:59, 12 December 2013

<syntaxhighlight lang="c">

  1. include<stdio.h>

int main() {

int *a;
*a=5;
printf("%d",a);
return 0;

}

</syntaxhighlight>

Solution

<syntaxhighlight lang="c"> int *a; </syntaxhighlight> This declares a as an integer pointer, meaning 'a' can point to any memory address which contains an int

<syntaxhighlight lang="c">

  • a = 5;

</syntaxhighlight> This makes the content of the address pointed to by 'a' 5. But 'a' is not pointing to any valid address (int *a assigns garbage value to 'a') and hence this assignment can cause segmentation fault

{{subst:wikEd}}





blog comments powered by Disqus

<syntaxhighlight lang="c">

  1. include<stdio.h>

int main() {

int *a;
*a=5;
printf("%d",a);
return 0;

}

</syntaxhighlight>

Solution[edit]

<syntaxhighlight lang="c"> int *a; </syntaxhighlight> This declares a as an integer pointer, meaning 'a' can point to any memory address which contains an int

<syntaxhighlight lang="c">

</syntaxhighlight> This makes the content of the address pointed to by 'a' 5. But 'a' is not pointing to any valid address (int *a assigns garbage value to 'a') and hence this assignment can cause segmentation fault




blog comments powered by Disqus