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Consider $L_1 = {a^nb^nc^md^m, m,n \ge 1}$

$L_2 = {a^nb^n, n \ge1}$
$L_3 = {(a+b)^*}

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Consider $L_1 = {a^nb^nc^md^m, m,n \ge 1}$

$L_2 = {a^nb^n, n \ge1}$ $L_3 = {(a+b)^*}