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Return to Kruskal Algorithm Implementation in C/C++.
<syntaxhighlight lang="C">
using namespace std;
int vi=0; char vertex[20];
struct nod
{ char x; struct nod *rep; struct nod *next; };
struct list {
nod node; struct nod *head; struct nod *tail;
};
class dsets {
list *s[20]; int nlist;
public:
dsets()
{ nlist = 0; }
void makeset(char a)
{ s[nlist] = new list; s[nlist]->node.x = a; s[nlist]->head = s[nlist]->tail = s[nlist]->node.rep = &(s[nlist]->node); s[nlist++]->node.next = NULL; }
list* findset(char a)
{ int i; nod *trav; for(i = 0; i < nlist; i++) { trav = s[i]->head; while(trav != NULL) { if(trav->x == a) return s[i]; trav = trav->next; } } return NULL; }
list* unin(list *a,list *b)
{ nod* trav = b->head; a->tail->next = b->head; a->tail = b->tail; while(trav != NULL) { trav->rep = a->head; trav = trav->next; }
b->head = b->tail = NULL; return a; }
void disp()
{ nod *trav; for(int i = 0; i < nlist; i++) { trav = s[i]->head; while(trav != NULL) { cout << trav->x << "\t"; trav = trav->next; } cout << endl; } } }; int main() {
char b, a, start; int forest[20]; char edge [20][2]; int cost[20]; int ei = 0; dsets disset; int c, d, i, u, fi = 0, j, t;
cout << "Enter the edges and cost\n0 to stop:\n "; while(1) { cin >> a; if(a == '0') break; edge[ei][0] = a;
cin >> b; edge[ei][1] = b; cin >> cost[ei++]; c = 0, d = 0; for(i = 0; i < vi; i++) { if(a == vertex[i]) { c++;
} if(b == vertex[i]) { d++; } } if(c == 0) { vertex[vi++] = a;
} if(d == 0) { vertex[vi++] = b;
} } for(i = 0; < ei; i++) for(j = 0; j < ei-i-1; j++) if(cost[j] > cost[j+1]) { t = cost[j]; cost[j] = cost[j+1]; cost[j+1] = t; for(int k = 0; k < 2; k++) { t = edge[j][k]; edge[j][k] = edge[j+1][k]; edge[j+1][k] = t; } } for(i = 0; i < vi; i++) disset.makeset(vertex[i]); for(i = 0; i < ei; i++) {
if(disset.findset(edge[i][0]) != disset.findset(edge[i][1])) { forest[fi++] = i; disset.unin(disset.findset(edge[i][0]),disset.findset(edge[i][1])); } } cout << "The minimum spanning tree of the entered graph is the one through the following edges\n"; for(i = 0; i < fi; i++) { cout << edge[forest[i]][0] << "\t"<<edge[forest[i]][1] << endl; } }
</syntaxhighlight>