Arjun Suresh (talk | contribs) |
Arjun Suresh (talk | contribs) |
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(C)2,2,4 | (C)2,2,4 | ||
− | '''(D)2, | + | '''(D)2,4,4''' |
===Solution=== | ===Solution=== | ||
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|} | |} | ||
− | a | + | a * a = e => order(a) = 2 |
+ | b * b * b * b = a * b * b = c * b = e => order(b) = 4 | ||
+ | c * c * c * c = a * c * c = b * c = e => order(c) = 4 | ||
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Let <math>G\{e,a,b,c\}</math> be an abelian group with <math>'e'</math> as an identity element. The order of the other elements are:
(A)2,2,3
(B)3,3,3
(C)2,2,4
(D)2,4,4
* | e | a | b | c |
---|---|---|---|---|
e | e | a | b | c |
a | a | e | c | b |
b | b | c | a | e |
c | c | b | e | a |
a * a = e => order(a) = 2 b * b * b * b = a * b * b = c * b = e => order(b) = 4 c * c * c * c = a * c * c = b * c = e => order(c) = 4
Let <math>G\{e,a,b,c\}</math> be an abelian group with <math>'e'</math> as an identity element. The order of the other elements are:
(A)2,2,3
(B)3,3,3
(C)2,2,4
(D)2,3,4
* | e | a | b | c |
---|---|---|---|---|
e | e | a | b | c |
a | a | e | c | b |
b | b | c | a | e |
c | c | b | e | a |
a and b have order 2(a * a = e and b * b = e). c has order 4 (since c * c = a and a * a = e)