Arjun Suresh (talk | contribs) (→For arbitrary CFGs G, G1 and G2 and an arbitrary regular set R) |
Arjun Suresh (talk | contribs) (→Note) |
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+ | {{alert|Please don't byheart this table. This is just to check your understanding |alert-danger}} | ||
+ | |||
:{| class="wikitable" | :{| class="wikitable" | ||
|+ align="top"|Grammar: Decidable and Undecidable Problems | |+ align="top"|Grammar: Decidable and Undecidable Problems | ||
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! <math>L(G_1) = L(G_2)</math> | ! <math>L(G_1) = L(G_2)</math> | ||
! <math>L(G_1) \cap L(G_2) = \phi</math> | ! <math>L(G_1) \cap L(G_2) = \phi</math> | ||
− | ! <math>L(G)</math> is finite | + | ! <math>L(G)</math> is regular? |
+ | ! $L(G)$ is finite? | ||
|- | |- | ||
|Regular Grammar | |Regular Grammar | ||
+ | | {{D}} | ||
| {{D}} | | {{D}} | ||
| {{D}} | | {{D}} | ||
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| {{D}} | | {{D}} | ||
| {{UD}} | | {{UD}} | ||
− | | {{ | + | | {{D}} |
| {{UD}} | | {{UD}} | ||
+ | | {{D}} | ||
| {{D}} | | {{D}} | ||
|- | |- | ||
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| {{D}} | | {{D}} | ||
| {{D}} | | {{D}} | ||
+ | | {{UD}} | ||
| {{UD}} | | {{UD}} | ||
| {{UD}} | | {{UD}} | ||
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|Context Sensitive | |Context Sensitive | ||
| {{D}} | | {{D}} | ||
+ | | {{UD}} | ||
| {{UD}} | | {{UD}} | ||
| {{UD}} | | {{UD}} | ||
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|Recursive | |Recursive | ||
| {{D}} | | {{D}} | ||
+ | | {{UD}} | ||
| {{UD}} | | {{UD}} | ||
| {{UD}} | | {{UD}} | ||
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|- | |- | ||
|Recursively Enumerable | |Recursively Enumerable | ||
− | | {{ | + | | {{UD}} |
+ | | {{UD}} | ||
| {{UD}} | | {{UD}} | ||
| {{UD}} | | {{UD}} | ||
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|} | |} | ||
+ | Checking if <math>L(CFG)</math> is finite is decidable because we just need to see if <math>L(CFG)</math> contains any string with length between <math>n</math> and <math>2n-1</math>, where <math>n</math> is the pumping lemma constant. If so, <math>L(CFG)</math> is infinite otherwise its finite. | ||
==Other Undecidable Problems == | ==Other Undecidable Problems == | ||
+ | [http://www.cis.upenn.edu/~jean/gbooks/PCPh04.pdf Proofs] | ||
+ | ===For arbitrary CFGs <math>G</math>, <math>G_1</math> and <math>G_2</math> and an arbitrary regular expression <math>R</math>=== | ||
+ | The following problems are '''undecidable''': | ||
+ | |||
+ | # Whether <math>(L(G_1))^\complement</math> is a CFL? | ||
+ | # Whether <math>L(G_1) \cap L(G2)</math> is a CFL? (undecidable for DCFG also) | ||
+ | # Whether <math>L(G_1) \cap L(G2)</math> is empty? (undecidable for DCFG also) | ||
+ | # Whether <math>L(G) = L(R)</math>? | ||
+ | # Whether <math>L(R) \subseteq L(G)</math>? | ||
+ | # Whether <math>G</math> is ambiguous? | ||
+ | # Whether <math>L(G)</math> is a DCFL? | ||
+ | # Whether <math>L(G)</math> is a regular language? | ||
+ | |||
+ | But whether <math>L(G) \subseteq L(R)</math> is decidable. (We can test if <math>L(G) \cap compl(L(R))</math> is <math>\phi</math>) | ||
+ | |||
+ | ===For arbitrary DCFGs <math>G</math>, <math>G_1</math> and <math>G_2</math> and an arbitrary regular expression <math>R</math>=== | ||
+ | The following problems are '''decidable''': | ||
+ | |||
+ | # Whether <math>(L(G_1))^\complement</math> is a DCFL? (trivial) | ||
+ | # Whether <math>L(G) = L(R)</math>? | ||
+ | # Whether <math>L(G) \subseteq (R)</math>? | ||
+ | # Whether <math>L(R) \subseteq L(G)</math>? | ||
+ | # Whether <math>L(G)</math> is a CFL? (trivial) | ||
+ | |||
+ | |||
− | + | {{Template:FBD}} | |
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− | + | [[Category: Automata Theory Notes]] | |
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− | + | [[Category: Compact Notes for Reference of Understanding]] |
Grammar | <math>w \in L(G)</math> | <math>L(G) = \phi</math> | <math>L(G) = \Sigma^*</math> | <math>L(G_1) \subseteq L(G_2)</math> | <math>L(G_1) = L(G_2)</math> | <math>L(G_1) \cap L(G_2) = \phi</math> | <math>L(G)</math> is regular? | $L(G)$ is finite? |
---|---|---|---|---|---|---|---|---|
Regular Grammar | D | D | D | D | D | D | D | D |
Det. Context Free | D | D | D | UD | D | UD | D | D |
Context Free | D | D | UD | UD | UD | UD | UD | D |
Context Sensitive | D | UD | UD | UD | UD | UD | UD | UD |
Recursive | D | UD | UD | UD | UD | UD | UD | UD |
Recursively Enumerable | UD | UD | UD | UD | UD | UD | UD | UD |
Checking if <math>L(CFG)</math> is finite is decidable because we just need to see if <math>L(CFG)</math> contains any string with length between <math>n</math> and <math>2n-1</math>, where <math>n</math> is the pumping lemma constant. If so, <math>L(CFG)</math> is infinite otherwise its finite.
The following problems are undecidable:
But whether <math>L(G) \subseteq L(R)</math> is decidable. (We can test if <math>L(G) \cap compl(L(R))</math> is <math>\phi</math>)
The following problems are decidable:
Grammar | <math>w \in L(G)</math> | <math>L(G) = \phi</math> | <math>L(G) = \Sigma^*</math> | <math>L(G_1) \subseteq L(G_2)</math> | <math>L(G_1) = L(G_2)</math> | <math>L(G_1) \cap L(G_2) = \phi</math> | <math>L(G)</math> is finite |
---|---|---|---|---|---|---|---|
Regular Grammar | D | D | D | D | D | D | D |
Det. Context Free | D | D | D | UD | ? | UD | D |
Context Free | D | D | UD | UD | UD | UD | D |
Context Sensitive | D | UD | UD | UD | UD | UD | UD |
Recursive | D | UD | UD | UD | UD | UD | UD |
Recursively Enumerable | D | UD | UD | UD | UD | UD | UD |
The following problems are undecidable:
Whether <math>R \subseteq L(G)</math> is decidable