Difference between revisions of "Unallocated Memory Reference"

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==={{Template:Author|Arjun Suresh|{{arjunweb}} }}===
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<syntaxhighlight lang="c">
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int *a;
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</syntaxhighlight>
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This declares a as an integer pointer, meaning 'a' can point to any memory address which contains an int
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<syntaxhighlight lang="c">
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*a = 5;
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</syntaxhighlight>
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This makes the content of the address pointed to by 'a' 5. But 'a' is not pointing to any valid address (int *a assigns garbage value to 'a') and hence this assignment can cause segmentation fault
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{{Template:FBD}}
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[[Category:Coding Questions]]

Latest revision as of 13:59, 14 April 2014

<syntaxhighlight lang="c">

  1. include<stdio.h>

int main() { 

int *a;
*a=5;
printf("%d",a);

return 0;

}

</syntaxhighlight>

Solution by Arjun Suresh

<syntaxhighlight lang="c"> int *a; </syntaxhighlight> This declares a as an integer pointer, meaning 'a' can point to any memory address which contains an int

<syntaxhighlight lang="c">

  • a = 5;

</syntaxhighlight> This makes the content of the address pointed to by 'a' 5. But 'a' is not pointing to any valid address (int *a assigns garbage value to 'a') and hence this assignment can cause segmentation fault




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Retrieved from "https://gatecse.in/w/index.php?title=Unallocated_Memory_Reference&oldid=2887"

<syntaxhighlight lang="c">

  1. include<stdio.h>

int main() { 

int *a;
*a=5;
printf("%d",a);

return 0;

}

</syntaxhighlight>