Difference between revisions of "Recursive calls"

 
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6. What value does function sum return when called with a value of 5?
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What value does function sum return when called with a value of 5?
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<syntaxhighlight lang="c">
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<syntaxhighlight lang="c" name="recursion_1">
 
int sum (int n) {
 
int sum (int n) {
 
   if (n < 1) return 1;
 
   if (n < 1) return 1;
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===Solution===
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==={{Template:Author|Arjun Suresh|{{arjunweb}} }}===
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We have to find the value of sum(1), sum(2), sum(3), sum(4) and sum(5)
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We have to find the value of sum(1), sum(2), sum(3), sum(4) and sum(5)
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sum(1) = 1 + sum(0) + sum(-1) = 1 + 1 + 1 = 3
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sum(2) = 2 + sum(1) + sum(0) = 2 + 3 + 1 = 6
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sum(3) = 3 + sum(2) + sum(1) = 3 + 6 + 3 = 12
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sum(4) = 4 + sum(3) + sum(2) = 4 + 12 + 6 = 22
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sum(5) = 5 + sum(4) + sum(3) = 5 + 22 + 12 = 39
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So, '''39''' is the answer
  
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sum(1) = 1 + sum(0) + sum(-1) = 1 + 1 + 1 = 3
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{{Template:FBD}}
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sum(2) = 2 + sum(1) + sum(0) = 2 + 3 + 1 = 6
 
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sum(3) = 3 + sum(2) + sum(1) = 3 + 6 + 3 = 12
 
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sum(4) = 4 + sum(3) + sum(2) = 4 + 12 + 6 = 22
 
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sum(5) = 5 + sum(4) + sum(3) = 5 + 22 + 12 = 39
 
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So, '''39''' is the answer
 
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<disqus/>
 
  
 
[[Category:Coding Questions]]
 
[[Category:Coding Questions]]

Latest revision as of 14:00, 14 April 2014

What value does function sum return when called with a value of 5? <syntaxhighlight lang="c" name="recursion_1"> int sum (int n) { 

  if (n < 1) return 1;
  else return n + sum(n - 1) + sum(n - 2);

} </syntaxhighlight>


Solution by Arjun Suresh

We have to find the value of sum(1), sum(2), sum(3), sum(4) and sum(5)
sum(1) = 1 + sum(0) + sum(-1) = 1 + 1 + 1 = 3
sum(2) = 2 + sum(1) + sum(0) = 2 + 3 + 1 = 6
sum(3) = 3 + sum(2) + sum(1) = 3 + 6 + 3 = 12
sum(4) = 4 + sum(3) + sum(2) = 4 + 12 + 6 = 22
sum(5) = 5 + sum(4) + sum(3) = 5 + 22 + 12 = 39
So, 39 is the answer




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6. What value does function sum return when called with a value of 5? <syntaxhighlight lang="c"> int sum (int n) { 

  if (n < 1) return 1;
  else return n + sum(n - 1) + sum(n - 2);

} </syntaxhighlight>


Solution[edit]

We have to find the value of sum(1), sum(2), sum(3), sum(4) and sum(5)

sum(1) = 1 + sum(0) + sum(-1) = 1 + 1 + 1 = 3

sum(2) = 2 + sum(1) + sum(0) = 2 + 3 + 1 = 6

sum(3) = 3 + sum(2) + sum(1) = 3 + 6 + 3 = 12

sum(4) = 4 + sum(3) + sum(2) = 4 + 12 + 6 = 22

sum(5) = 5 + sum(4) + sum(3) = 5 + 22 + 12 = 39

So, 39 is the answer



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