Arjun Suresh (talk | contribs) (Created page with "===What's the output?=== <syntaxhighlight lang="c"> int main() { int arr[3] = {2, 3, 4}; char *p; p = (char*)arr; printhex(p); printf("...") |
Arjun Suresh (talk | contribs) |
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printf("\n%p %d\n",p,*p); | printf("\n%p %d\n",p,*p); | ||
return 0; | return 0; | ||
| + | } | ||
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So, 2 will be stored as follows: | So, 2 will be stored as follows: | ||
| − | 1000: 0 0 0 0 0 0 0 2 (each char is hexa decimal and assume int takes 4 bytes) | + | 1000: 0 0 0 0 0 0 0 2 (each char is hexa decimal and assume int takes 4 bytes) |
| − | 1004: 0 0 0 0 0 0 0 3 | + | 1004: 0 0 0 0 0 0 0 3 |
| − | Now, %d, *p will print the first 4 bytes starting at 1000, that is 2. | + | Now, %d, *p will print the first 4 bytes starting at 1000, that is 2. When p is incremented, it will go to 1001, as p is a char pointer. |
| − | + | 1001: 0 0 0 0 0 0 0 0 | |
| − | 1001: 0 0 0 0 0 0 0 0 | ||
| − | + | So, output will be 0. | |
<syntaxhighlight lang="c"> int main() {
GATECSE int arr[3] = {2, 3, 4};
char *p;
p = (char*)arr;
printhex(p);
printf("%p %d ",p, *p);
p = p+1;
printhex(p);
printf("\n%p %d\n",p,*p);
return 0;
}
</syntaxhighlight>
(A) 2 3
(B) 2 0
(C) 1 0
(D) Garbage value
Assume start location of arr s 1000. So, 2 will be stored as follows:
1000: 0 0 0 0 0 0 0 2 (each char is hexa decimal and assume int takes 4 bytes) 1004: 0 0 0 0 0 0 0 3
Now, %d, *p will print the first 4 bytes starting at 1000, that is 2. When p is incremented, it will go to 1001, as p is a char pointer.
1001: 0 0 0 0 0 0 0 0
So, output will be 0.
<syntaxhighlight lang="c"> int main() {
int arr[3] = {2, 3, 4};
char *p;
p = (char*)arr;
printhex(p);
printf("%p %d ",p, *p);
p = p+1;
printhex(p);
printf("\n%p %d\n",p,*p);
return 0;
</syntaxhighlight>
(A) 2 3
(B) 2 0
(C) 1 0
(D) Garbage value
Assume start location of arr s 1000. So, 2 will be stored as follows:
1000: 0 0 0 0 0 0 0 2 (each char is hexa decimal and assume int takes 4 bytes) 1004: 0 0 0 0 0 0 0 3
Now, %d, *p will print the first 4 bytes starting at 1000, that is 2. when p is incremented, it will go to 1001, as p is a char pointer. 1001: 0 0 0 0 0 0 0 0
so, output will be 0.