Arjun Suresh (talk | contribs) (Created page with " <quiz display="simple"> {'''What will be the output??''' <syntaxhighlight lang="c"> #include <stdio.h> #include <string.h> int main() { int x = 8, y = 1; switch(x--, y...") |
Arjun Suresh (talk | contribs) |
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+33 55 | +33 55 | ||
-33 56 | -33 56 | ||
− | || | + | || x--, y++ will return the value of y which is 1, as comma operator always returns the right value. Hence, switch case starts with 1. Before starting the switch case, x is decremented and y incremented also. So, in case 1, x is 7 and y is 2. x is changed to 56 in case 1. Because of no break, all cases are evaluated here. So, in case 2, x becomes 28 and y becomes 56. In case 3 nothing happens. In case 4, y becomes 55 and finally in default case x becomes 33. |
</quiz> | </quiz> |
<quiz display="simple"> {What will be the output?? <syntaxhighlight lang="c">
int main() {
int x = 8, y = 1; switch(x--, y++) { case 1: x*=8; case 2: y*= x/=2; case 3: case 4: y--; default: x+=5; } printf("%d %d", x, y);
} </syntaxhighlight> |type="()" /} -64 2 -64 1 +33 55 -33 56 || x--, y++ will return the value of y which is 1, as comma operator always returns the right value. Hence, switch case starts with 1. Before starting the switch case, x is decremented and y incremented also. So, in case 1, x is 7 and y is 2. x is changed to 56 in case 1. Because of no break, all cases are evaluated here. So, in case 2, x becomes 28 and y becomes 56. In case 3 nothing happens. In case 4, y becomes 55 and finally in default case x becomes 33.
</quiz>
<quiz display="simple"> {What will be the output?? <syntaxhighlight lang="c">
int main() {
int x = 8, y = 1; switch(x--, y++) { case 1: x*=8; case 2: y*= x/=2; case 3: case 4: y--; default: x+=5; } printf("%d %d", x, y);
} </syntaxhighlight> |type="()" /} -64 2 -64 1 +33 55 -33 56 ||
</quiz>