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(A) $\neg Q$$&#9633¬P$
+
(A) $\neg Q ¬P$
  
(B) '''$P&#9633¬Q$'''
+
(B) '''$P□\neg Q$'''
  
(C) $¬P&#9633Q$
+
(C) $\neg P□Q$
 
 
(D) $¬P&#9633¬Q$
+
(D) $\neg P□ \negQ$
 
==={{Template:Author|Happy Mittal|{{mittalweb}} }}===
 
==={{Template:Author|Happy Mittal|{{mittalweb}} }}===
  
If we compare column of $P□Q$ in table with $P ∨ Q$, we need both F in $3^{rd}$ row of table, and for that we need  
+
If we compare column of $P\neg Q$ in table with $P ∨ Q$, we need both F in $3^{rd}$ row of table, and for that we need  
$&not;Q$ instead of $Q$. So $P &or; Q$ is equivalent to $P&#9633&not;Q$, and therefore, option <b>(B)</b> is correct.
+
$\negQ$ instead of $Q$. So $P &or; Q$ is equivalent to $P□\negQ$, and therefore, option <b>(B)</b> is correct.
  
 
{{Template:FBD}}
 
{{Template:FBD}}

Revision as of 19:47, 14 July 2014

The binary operation □ is defined as follows

P Q P□Q
T T T
T F T
F T F
F F T

(A) $\neg Q □ ¬P$

(B) $P□\neg Q$

(C) $\neg P□Q$

(D) $\neg P□ \negQ$

Solution by Happy Mittal

If we compare column of $P\neg Q$ in table with $P ∨ Q$, we need both F in $3^{rd}$ row of table, and for that we need $\negQ$ instead of $Q$. So $P ∨ Q$ is equivalent to $P□\negQ$, and therefore, option (B) is correct.




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The binary operation □ is defined as follows

P Q P□Q
T T T
T F T
F T F
F F T

(A) $\neg Q$$&#9633¬P$

(B) $P&#9633¬Q$

(C) $¬P&#9633Q$

(D) $¬P&#9633¬Q$

Solution by Happy Mittal[edit]

If we compare column of $P□Q$ in table with $P ∨ Q$, we need both F in $3^{rd}$ row of table, and for that we need $¬Q$ instead of $Q$. So $P ∨ Q$ is equivalent to $P&#9633¬Q$, and therefore, option (B) is correct.




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