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− | A man visits a couple who have 2 children. one of the children, a boy, comes into the room. find the probability p that the other is also a boy. | + | A man visits a couple who have 2 children. one of the children, a boy, comes into the room. find the probability <math>p</math> that the other is also a boy. |
− | (a)1/3 (b)2/3 '''(c)1/2''' (d)3/4 | + | (a)1/3 |
+ | |||
+ | (b)2/3 | ||
+ | |||
+ | '''(c)1/2''' | ||
+ | |||
+ | (d)3/4 | ||
===Solution=== | ===Solution=== |
A man visits a couple who have 2 children. one of the children, a boy, comes into the room. find the probability <math>p</math> that the other is also a boy.
(a)1/3
(b)2/3
(c)1/2
(d)3/4
Since, it's given that the first one is a boy, the second event is independent of the first and the probability is 1/2. Had it been "one of the children is a boy" instead of "first one is a boy" then the probability of two children being boys would have been 1/3 (sample space BB, BG, GB).
A man visits a couple who have 2 children. one of the children, a boy, comes into the room. find the probability <math>p</math> that the other is also a boy.
(a)1/3
(b)2/3
(c)1/2
(d)3/4
Since, it's given that the first one is a boy, the second event is independent of the first and the probability is 1/2. Had it been "one of the children is a boy" instead of "first one is a boy" then the probability of two children being boys would have been 1/3 (sample space BB, BG, GB).