Arjun Suresh (talk | contribs) (Created page with "Complexity <math>\theta(n)</math> No. of swaps in the worst case = <math> \lfloor n/2 \rfloor</math> <syntaxhighlight lang="c" name="largesum"> #include <stdio.h> #include<s...") |
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<syntaxhighlight lang="c" name="largesum"> | <syntaxhighlight lang="c" name="largesum"> | ||
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int main(void) { | int main(void) { | ||
− | char a[1000], b[1000], c[1000], carry; | + | char a[1000], b[1000], c[1000], carry; //a and b hold the input numbers and c hold the output number. Each array entry is a digit |
− | int al, bl; | + | int al, bl; //for storing the number of digits of the two input numbers |
printf("Enter the first number "); | printf("Enter the first number "); | ||
al = read(a); | al = read(a); | ||
− | fflush(stdin); | + | fflush(stdin); //Removes any previous character entered via keyboard |
printf("Enter the second number "); | printf("Enter the second number "); | ||
bl = read(b); | bl = read(b); | ||
− | int l = al > bl? al:bl; | + | int l = al > bl? al:bl;//l stores the no.of digit of output which might also become l+1 because of carry from MSB |
int i = l; | int i = l; | ||
carry = 0; | carry = 0; | ||
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carry = val/10; | carry = val/10; | ||
} | } | ||
− | while(al > 0) | + | while(al > 0)//If a has more digits than b |
{ | { | ||
char val = a[--al] + carry; | char val = a[--al] + carry; | ||
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carry = val/10; | carry = val/10; | ||
} | } | ||
− | while(bl > 0) | + | while(bl > 0)//If b has more digits than a |
{ | { | ||
char val = b[--bl] + carry; | char val = b[--bl] + carry; | ||
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carry = val/10; | carry = val/10; | ||
} | } | ||
− | c[0] = carry; | + | c[0] = carry;//Assigning the final carry |
printf("sum = "); | printf("sum = "); | ||
print(c, l+1); | print(c, l+1); | ||
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if(!isdigit(c)) | if(!isdigit(c)) | ||
break; | break; | ||
− | a[i++] = c-48; | + | a[i++] = c-48;//getchar returns the ASCII. So, for 1 it returns 49. Subtracting 48, we get the actual int value entered via keyboard |
} | } | ||
return i; | return i; | ||
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</syntaxhighlight> | </syntaxhighlight> | ||
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<syntaxhighlight lang="c" name="largesum">
void print(char *a, int l); int read(char *a);
int main(void) { char a[1000], b[1000], c[1000], carry; //a and b hold the input numbers and c hold the output number. Each array entry is a digit int al, bl; //for storing the number of digits of the two input numbers printf("Enter the first number "); al = read(a); fflush(stdin); //Removes any previous character entered via keyboard printf("Enter the second number "); bl = read(b); int l = al > bl? al:bl;//l stores the no.of digit of output which might also become l+1 because of carry from MSB int i = l; carry = 0; while(al > 0 && bl > 0) { char val = a[--al] + b[--bl] + carry; c[i--] = val %10; carry = val/10; } while(al > 0)//If a has more digits than b { char val = a[--al] + carry;
c[i--] = val %10; carry = val/10;
} while(bl > 0)//If b has more digits than a { char val = b[--bl] + carry;
c[i--] = val %10; carry = val/10;
} c[0] = carry;//Assigning the final carry printf("sum = "); print(c, l+1); return 0; }
int read(char *a) { char c; int i = 0; while(1) { c = getchar(); if(!isdigit(c)) break; a[i++] = c-48;//getchar returns the ASCII. So, for 1 it returns 49. Subtracting 48, we get the actual int value entered via keyboard } return i; } void print(char *a, int l) { int i; if(a[0] != 0) printf("%d",a[0]); for(i = 1; i < l; i++) { printf("%d", a[i]); } printf("\n"); }
</syntaxhighlight>
<syntaxhighlight lang="c" name="largesum">
void print(char *a, int l); int read(char *a);
int main(void) { char a[1000], b[1000], c[1000], carry; //a and b hold the input numbers and c hold the output number. Each array entry is a digit int al, bl; //for storing the number of digits of the two input numbers printf("Enter the first number "); al = read(a); fflush(stdin); //Removes any previous character entered via keyboard printf("Enter the second number "); bl = read(b); int l = al > bl? al:bl;//l stores the no.of digit of output which might also become l+1 because of carry from MSB int i = l; carry = 0; while(al > 0 && bl > 0) { char val = a[--al] + b[--bl] + carry; c[i--] = val %10; carry = val/10; } while(al > 0)//If a has more digits than b { char val = a[--al] + carry;
c[i--] = val %10; carry = val/10;
} while(bl > 0)//If b has more digits than a { char val = b[--bl] + carry;
c[i--] = val %10; carry = val/10;
} c[0] = carry;//Assigning the final carry printf("sum = "); print(c, l+1); return 0; }
int read(char *a) { char c; int i = 0; while(1) { c = getchar(); if(!isdigit(c)) break; a[i++] = c-48;//getchar returns the ASCII. So, for 1 it returns 49. Subtracting 48, we get the actual int value entered via keyboard } return i; } void print(char *a, int l) { int i; if(a[0] != 0) printf("%d",a[0]); for(i = 1; i < l; i++) { printf("%d", a[i]); } printf("\n"); }
</syntaxhighlight>