(Created page with "<quiz display="simple"> {'''What will be the output of the following code?''' <syntaxhighlight lang="c"> #include<stdio.h> int main(){ int a = 5; int* p = &a; printf("%...")
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Revision as of 21:04, 15 June 2014

<quiz display="simple"> {What will be the output of the following code? <syntaxhighlight lang="c">

  1. include<stdio.h>

int main(){

 int a = 5;
 int* p = &a;
 printf("%d", ++*p);

} </syntaxhighlight> |type="{}" /} { 6 } ||p is pointing to the address of a. *p will return the content of a which is 5 and ++ will increment it to 6.


{What will be the output of the following code? <syntaxhighlight lang="c">

  1. include<stdio.h>

int main(){

 char a[] = "Hello World";
 char* p = &a;
 printf("%s", p+2 );

} </syntaxhighlight> |type="()" /} -Compiler Error -World +llo World -Runtime Error

||Since p is a char pointer p+2 will add 2 to p (since sizeof(char) is 1). So, p+2 will be pointing to the string "llo World"

{What will be the output of the following code? <syntaxhighlight lang="c">

  1. include<stdio.h>

int main(){

 int a;
 int* p = &a;
 printf("%zu", sizeof( *(char*)p  ));

} </syntaxhighlight> |type="()" /}

+1 -2 -4 -Compile Error

||p is typecasted to char pointer and then dereferenced. So, returned type will be char and sizeof(char) is 1

</quiz>

<quiz display="simple"> {What will be the output of the following code? <syntaxhighlight lang="c">

  1. include<stdio.h>

int main(){

 int a = 5;
 int* p = &a;
 printf("%d", ++*p);

} </syntaxhighlight> |type="{}" /} { 6 } ||p is pointing to the address of a. *p will return the content of a which is 5 and ++ will increment it to 6.


{What will be the output of the following code? <syntaxhighlight lang="c">

  1. include<stdio.h>

int main(){

 char a[] = "Hello World";
 char* p = &a;
 printf("%s", p+2 );

} </syntaxhighlight> |type="()" /} -Compiler Error -World +llo World -Runtime Error

||Since p is a char pointer p+2 will add 2 to p (since sizeof(char) is 1). So, p+2 will be pointing to the string "llo World"

{What will be the output of the following code? <syntaxhighlight lang="c">

  1. include<stdio.h>

int main(){

 int a;
 int* p = &a;
 printf("%zu", sizeof( *(char*)p  ));

} </syntaxhighlight> |type="()" /}

+1 -2 -4 -Compile Error

||p is typecasted to char pointer and then dereferenced. So, returned type will be char and sizeof(char) is 1

</quiz>