Arjun Suresh (talk | contribs) |
Arjun Suresh (talk | contribs) |
||
| Line 19: | Line 19: | ||
[[Category: GATE2010]] | [[Category: GATE2010]] | ||
| − | [[Category: Probability questions]] | + | [[Category: Probability questions from GATE]] |
Consider a company that assembles computers. The probability of a faulty assembly of any computer is $p$. The company therefore subjects each computer to a testing process. This testing process gives the correct result for any computer with a probability of $q$. What is the probability of a computer being declared faulty?
(A) $pq + (1 - p)(1 - q)$
(B) $(1 - q)p$
(C) $(1 - q)p$
(D) $pq$
P(declared faulty) = P(actually faulty)*P(declared faulty|actually faulty) + P(not faulty)*P(declared faulty|not faulty) = $p*q + (1-p)*(1-q)$
So, option (A) is correct.
Consider a company that assembles computers. The probability of a faulty assembly of any computer is $p$. The company therefore subjects each computer to a testing process. This testing process gives the correct result for any computer with a probability of $q$. What is the probability of a computer being declared faulty?
(A) $pq + (1 - p)(1 - q)$
(B) $(1 - q)p$
(C) $(1 - q)p$
(D) $pq$
P(declared faulty) = P(actually faulty)*P(declared faulty|actually faulty) + P(not faulty)*P(declared faulty|not faulty) = $p*q + (1-p)*(1-q)$
So, option (A) is correct.
GATECSE