(Created page with "Page table are stored in memory , which has access time of 100 ns. The TLB holding 8 page table entries, has an access time of 10 ns. Using execution of process , it is found...")
 
 
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Page table are stored in memory , which has access time of 100 ns. The TLB holding 8 page table entries, has an access time of 10 ns.  
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Page tables are stored in memory , which has access time of 100 ns. The TLB holding 8 page table entries, has an access time of 10 ns.  
 
Using execution of process , it is found that 85 % of the time, a required page table entry exist in TLB and only 2 % of the total references causes page fault. Page replacement time is 2 ms . Calculate the effective memory access time , assuming page memory access requires 2 memory accesses and TLB requires one memory access.  
 
Using execution of process , it is found that 85 % of the time, a required page table entry exist in TLB and only 2 % of the total references causes page fault. Page replacement time is 2 ms . Calculate the effective memory access time , assuming page memory access requires 2 memory accesses and TLB requires one memory access.  
  
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==={{Template:Author|Arjun Suresh|{{arjunweb}} }}===
 
==={{Template:Author|Arjun Suresh|{{arjunweb}} }}===
  
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Let S be average memory access time.
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<!--
 +
S = Time when TLB hits (85 %)+ Time when TLB misses (15%) + Time for page faults (2% of total memory accesses)
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= 0.85 * (10+100)
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+0.15 * (10+100+200 +  2,000,000*2/100)
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= 0.85 * 110
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+0.15(80620)
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= 40140
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-->
 
{{Template:FBD}}
 
{{Template:FBD}}
  
 
[[Category: Non-GATE Questions from OS]]
 
[[Category: Non-GATE Questions from OS]]

Latest revision as of 14:39, 20 July 2014

Page tables are stored in memory , which has access time of 100 ns. The TLB holding 8 page table entries, has an access time of 10 ns. Using execution of process , it is found that 85 % of the time, a required page table entry exist in TLB and only 2 % of the total references causes page fault. Page replacement time is 2 ms . Calculate the effective memory access time , assuming page memory access requires 2 memory accesses and TLB requires one memory access.

A) 38120 ns B) 40000 ns C) 40120 ns D) None

Solution by Arjun Suresh

Let S be average memory access time.



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Page tables are stored in memory , which has access time of 100 ns. The TLB holding 8 page table entries, has an access time of 10 ns. Using execution of process , it is found that 85 % of the time, a required page table entry exist in TLB and only 2 % of the total references causes page fault. Page replacement time is 2 ms . Calculate the effective memory access time , assuming page memory access requires 2 memory accesses and TLB requires one memory access.

A) 38120 ns B) 40000 ns C) 40120 ns D) None

Solution by Arjun Suresh[edit]

Let S be average memory access time.



blog comments powered by Disqus