Pointer qn 1 Revision as of 12:01, 18 March 2015 by Arjun Suresh (talk | contribs) (→‎{{Template:Author|Arjun Suresh|{{arjunweb}} }}) (diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

What's the output?

<syntaxhighlight lang="c" name="pointer_1"> int main() {

       int arr[3] = {2, 3, 4};
       char *p;
       p = (char*)arr;
       printf("%d ", *p);
       p = p+1;
       printf("%d\n", *p);
       
       return 0;

}

</syntaxhighlight>

(A) 2 3

(B) 2 0

(C) 1 0

(D) Garbage value

Solution by Arjun Suresh

Assume start location of arr is 1000. So, the first two elements of the array will be stored in memory as follows:

1000: 0 0 0 0 0 0 0 2 (hexa decimal representation and assuming int takes 4 bytes and assuming least significant byte is stored at highest address(little-endian))
1004: 0 0 0 0 0 0 0 3

Now, %d, *p will print the first 4 bytes starting at 1000, that is 2. When p is incremented, it will go to 1001, as p is a char pointer.

1001: 0 0 0 0 0 0 0 0

So, output will be 0.

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