A.In the cycle stealing mode of DMA, one word of data is transferred between an I/O device and main memory in a stolen cycle ans.True (as defination)B.For bulk data transfer, the burst mode of DMA has a higher throughput than the cycle stealing modeans.True(as define, through as compared to bulk data, for burst mode through put will be equal to 1 as bulk of data will be transferd at once but with cycle stealing mode transfer will take more time and throughput will be less)C.Programmed I/O mechanism has a better CPU utilization than the interrupt driven I/O mechanismans.False (Programmed i/o is like [...]

A,B,D is the answer. The return value is 4. [...]

The fastest way to solve these type of question is with the help of Venn Diagram. For this question, Venn Diagram will look like this :  P(A) = 0.3, P(B) = 0.5, P(A  $\cap$ B) = 0.1Let's try to observe every option one by one. Option A : The two events 𝐴 and 𝐵 are independentTwo events are said to be Independent when : P(A $\cap$ B) = P(A).P(B)P(A $\cap$ B) = 0.1P(A).P(B) = 0.3 x 0.5 = 0.15P(A $\cap$ B) $\neq$ P(A).P(B)So, Option A is Incorrect. Option B : P(A $\cup$ B) = 0.7.P(A $\cup$ B) = P(A) + P(B) - P(A $\cap$ B) = 0.3 + 0.5 - 0.1 = 0.7So, Option B is Correct. Option C : [...]

nth group starts with $(n-1)$$^{2}$ $+$ $1$ and ends with $n$$^{2}$ and every group consists $2n-1$ numbers $15th$ group starts with 196 and ends with $225$ $sum$ = $\frac{No of terms}{2}$ * $[first$ $term$+$last$ $term]$ = $\frac{29}{2} * [(196+1) + 225]$ = $6119$ [...]

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Another Approach: It is given 4th term=8 so consider an AP with 7 terms as following a-3d , a-2d , a-d , a , a+d , a+2d , a+3d Here 4th term = a = 8 Sum of the above series= 7*8=56 Answer= 56 [...]