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What Resources to Use for GATE CSE Preparation?

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How to use Standard materials for GATE preparation

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Is solving previous year questions enough?

July 10, 2016 by arjun 3 Comments

Enough for? It is enough to surely get 30-50 marks but that won’t get you even to an NIT unless you have some reservation. If you carefully read the below points you can get higher marks. How to solve? Getting answer to the previous year GATE questions takes you nowhere as in GATE questions RARELY […]

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CBSE (UGC) NET Question Papers for CSE

June 28, 2016 by arjun 1 Comment

CBSE NET previous year papers for Computer Science & Engineering

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LIFE CHANGING SKILLS

May 17, 2016 by bikram Leave a Comment

Go Offline First and foremost, forget about social media for a month. You will instantly notice how longer your day can be without it. This will let you literally maximize your time. Now your task is to use that time properly. Define Your Goals Clarity does really matter. Before committing to certain things take some time […]

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SSH Without Password

April 19, 2016 by ibia Leave a Comment

The basis of this is that your ID must be in the list of authorized hosts in the server. So, for password-less login to work, generate your public key, and append it to the authorized_hosts file in the server. To create a public key, from terminal do ssh-keygen -t rsa To copy to authorized_hosts file […]

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GATE Overflow
Aptitude Overflow

Answered: NIELIT 2021 Dec Scientist B - Section B: 94

To find the complement of any boolean expression following steps are there: Convert $0$ to $1$ and vice versa. Convert $+$ to $*$ and vice versa Take variables complement, $A\leftrightharpoons \bar A$ So complement of the given expression is as follow: $Y=ABC+AB\bar C+\bar A\bar BC+\bar ABC$ $Y=AB(C+\bar C)+\bar AC(\bar B+B)$ $Y=AB+\bar AC$ $Y^c=(\bar A+\bar B)*(A+\bar C)$ Option $(A)$ is correct. [...]

Answered: NIELIT 2021 Dec Scientist B - Section B: 62

We have 9000 4 digit numbers. now we need 4 digit number contain at most 2 different digit which is equal to total number – all 4 digits different – 3 digits different. =9000- 9*9*8*7 -9*9*8*6 [3 different digit can place 6 ways that’s why multiply by 6 in 3 different digit] = 576 (option A) [...]

Answered: NIELIT 2021 Dec Scientist B - Section B: 66

Dijkstra Algorithm cannot be applied on graph which has negatives edges as well as graph with negative cycle. If the graph has negative edge it still can give you wrong results. correct ans B. PS. https://www.quora.com/What-are-the-limitations-of-Dijkstras-algorithm-greedy-approach [...]

Answered: NIELIT 2021 Dec Scientist B - Section B: 69

page number offset m-n bit n nit logical address space =2^m. so m bit require to represent the address space page size=2^n. so n bit require for offset. so page number =m-n. Ans is option B. [...]

Answered: NIELIT 2021 Dec Scientist B - Section B: 87

Answered: NIELIT 2021 Dec Scientist B - Section B: 87

$(503201)_6\rightarrow(39601)_{10}\rightarrow(21222301)_4$ Base $6$ to base $10$ conversion: $(1*6^0+0*6^1+2*6^2+3*6^3+0*6^4+5*6^5=(39601)_{10}$ Now base $10$ to base $4$ conversion: Option $(C)$ is correct. [...]

Answered: NIELIT 2021 Dec Scientist B - Section B: 70

correct answer option B. A bottom up parser generates Reverse of Rightmost derivation . PS:-https://www.d.umn.edu/~rmaclin/cs5641/Notes/Lecture8.pdf [...]

Answered: CAT2020-1: 54

Given that, area of rectangular metal sheet $ = 135 \; \text{sq inches}.$ Now, we can draw the diagram. Diagram Let the length and breadth of the rectangle be $l$ and $b$ respectively. Let the radius of a circle be $r \; \text{inches}.$ $lb = 135$ Let the painted area be $3x.$ Then left unpainted area will be $2x.$ So, $3x + 2x = 135$ $\Rightarrow 5x = 135$ $ \Rightarrow \boxed{x = 27}$ The painted area (area of circle) $ = 3 \times 27 = 81 \; \text {sq inches}.$ The left unpainted area $ = 2 \times 27… [...]

Answered: CAT2020-1: 53

Let the volumes of $ A, B,$ and $C$ be $3x, 4x$ and $7x.$ Weights of the same volume of the metals $ A, B,$ and $C$ are in the ratio $5:2:6.$ So, the ratio of the weights in the overall alloy. $A:B:C = (3x \times5) : (4x \times 2) : (7x \times 6)$ $ \Rightarrow A:B:C = 15 : 8 : 42 $ $\therefore$ The weight of metal $C = 130 \times \frac{42}{65} = 84 \; \text{kg}.$ Short Method$:$ $\qquad \qquad A \quad B \quad C$ Volume$: \quad3 : 4 : 6$ Weight$: \quad 5 : 2 : 6 \; (1… [...]

Answered: CAT2020-1: 52

Given that, Veeru$:$ Principle $(P_{1}) = \text{Rs} \; 10000$ Rate $(R_{1}) = 5 \%$ Joy$:$ Principle $(P_{2}) = \text{Rs} \; 8000$ Rate $(R_{2}) = 10 \%$ Let the time after Joy’s investment, when the balances become equal be $n$ years. i.e., principal plus accumulated interest $ P_{1} + \left[ \dfrac{P_{1} \times R_{1} \times (n+2)}{100} \right] = P_{2} + \left[ \dfrac{P_{2} \times R_{2} \times (n)}{100} \right] $ $ \Rightarrow 10000 + \left[ \dfrac {10000 \times 5 \times (n+2)}{100} \right] = 8000 + \left[ \dfrac{ 8000 \times 10 \times (n)}{100} \right] $ $ \Rightarrow 2000 + 500 (n+2) = 800n $ $ \Rightarrow 2000 + 500n + 1000 = 800n… [...]

Answered: CAT2020-1: 51

Given that, the product of $3- \text{digit}$ numbers is more than $2$ but less than $7.$ Let the $3- \text{digit}$ number be $xyz.$ Then, $ 2< x \times y \times z < 7 $ $ \Rightarrow x \times y \times z = 3 (or) 4 (or) 5 (or) 6 $ Case$1:$ When $x \times y \times z = 3$ Three possibilities. Case$2:$ When $x \times y \times z = 4$ Six possibilities. Case$3:$ When $x \times y \times z = 5$ Three possibilities. Case$4:$ When $x \times y \times z = 6$… [...]

Answered: CAT2020-3: 75

Let us assume that the total marks is $100x$ Then Bishnu marks =$52x$ Asha marks = $64x$ Now according to the question, if $y$ is the mark obtained by Ramesh, $52x=y-23 \longrightarrow (1)$ $64x=y+34 \longrightarrow (2)$ Equation $(2)-(1)$ $\Rightarrow 12x=57 $ $\Rightarrow x= \frac{57}{12}$ $\therefore 84x=\frac{57*84}{12}=399$ Note: $84x$ means scored obtain by Gita that is $84 \%$ So option $B$ is correct. [...]

Answered: CAT2020-3: 52

Let us assume Tom age is $x$ then: Dick’s age= $3x$ Harry’s age=$2.3x=6x$ Now according to the given question, Dick’s age is 1 year less than the average age of all three, $\therefore 3x=\left (\frac{3x+6x+x}{3} \right )-1$ $\Rightarrow 3x=\left (\frac{10x}{3} \right )-1$ $\Rightarrow 1=\frac{10x}{3}-3x$ $\Rightarrow 1=\frac{10x-9x}{3}$ $\Rightarrow 1=\frac{x}{3}$ $\Rightarrow x=3$ So Tom age is $3$ year, Harry’s age is $=6x=6*3=18$ year. $\therefore$ Harry’s age is $18$ year. [...]

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