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Answered: gate zeal

Option B:The barrier implementation may lead to a deadlock if two barrier in invocations are used in immediate successionisn't that mean : barrier();barrier();Let there are n processes namely 1 to n.All processes are out from while (process_arrived !=n) of first barrier. --> process_arrived = n1 to n-1 are entered second barrier after completion of first barrier.  --> process_left = n-1 and process_arrived may be n + 1 or n+2 or ....... n+(n-1) but not nTherefore Now all those are struck at while(process_arrived !=n);  Meanwhile, process $P_n$ take charge of semaphore and made process_left = n and process_arrived = 0.Now entered into the 2nd barrier, [...]

Answered: College exam

Inital position + 4 times rotate in one direction = initial position. Therefore 6 times left = 6-4 = 2 times left and 7 times right = 3 times right Total shift from initial position = 2 left + 3 right + 2 left = 4 left + 3 right = 1 left from initial if final = south, then initial = south - left = south + right = West [...]

Answered: UGC NET CSE | October 2022 | Part 1 | Question: 84

NO OF TRACKS:   80 NO OF BYTES PER SECTOR: 128 BYTESTOTAL STORAGE CAPACITY = (NO OF TRACKS) x (NO OF SECTORS PER TRACK) x (NO OF BYTES PER SECTOR)163840 = 80 x S x 128S = 163840 / (80 x 128)S = 163840 / 10240S = 16ANS : OPTION - D  [...]

Answered: GATE CSE 2021 Set 2 | Question: 23

15 is a factor of 255. i.e; 15 x 17 = 255observing the given code: if (y > x) condition will be executed recursively keeping the x value intact i.e; 15 decreasing y's value by 15 every time, exactly 16 times and at 17th function call y value will be 15 i.e; SomeFunction(15, 15) and hence if (x == y) condition will satisfy and will return 15.  [...]

Answered: ISRO 2024

B will be the answer becoz aaSb aaaaSbb aaaaTbb aaaaTbbb aaaaabbb and 2nd one can't be generated [...]

Answered: GO Classes Test Series 2024 | Mock GATE | Test 14 | Question: 35

Answer is d as it will only have 3,6,9,12.......means 3n b [...]

Answered: CAT 2015 | Question: 31

c [...]

Answered: CAT 2023 Set-3 | Quantitative Aptitude | Question: 2

B [...]

Answered: CAT 2023 Set-3 | Quantitative Aptitude | Question: 3

d [...]

Answered: CAT 2023 Set-3 | Quantitative Aptitude | Question: 5

9 [...]

Answered: CAT 2023 Set-3 | Quantitative Aptitude | Question: 1

B [...]

Answered: CAT 2020 Set-3 | Question: 52

Given information: - Dick is thrice as old as Tom. Let Tom's age be x. - Harry is twice as old as Dick. - Dick's age is 1 year less than the average age of all three. Step 1: Express Dick's age in terms of Tom's age (x). Dick's age = 3x Step 2: Express Harry's age in terms of Dick's age. Harry's age = 2 × Dick's age = 2 × 3x = 6x Step 3: Set up an equation for Dick's age being 1 year less than the average age of all three. Dick's age = (Tom's age [...]