Given, $ab + cd = pqr$ where, r = sum of bits b and d            q = sum of bits a, c and the carry generated from the summation of b and d            p = sum of carry generated by summation of bits a, c and the carry generated by summation of bits b and d $r = \text{sum of bits b and d} = b \oplus d = (\neg b \wedge d) \lor (b \wedge \neg d)$     $s = \text {summation of bits a and c} = (\neg a \wedge c) \lor (a \wedge \neg c)$ $t [...]

S2: R1(x);r2(z);r3(x);r1(z);r2(y);r3(y);w1(x);w2(z);w3(y);w2(y) Please help [...]

Option D [...]

The answer should be C) Bina. Here is a stepwise solution ->  1. China is sitting 3rd to the left of Dipa.(both facing inside) 2. Elina is not sitting adjacent to either of China or Dipa => only one position is left for her 3. One sitting between Dipa and Fiona will be facing outside => Dipa and Fiona need to have one empty place between them, this fixes the position of Fiona. 4. Gita sits 3rd to the right of Aina => it is not possible if we consider that Aina is facing inside(no empty place with a gap [...]

nth group starts with $(n-1)$$^{2}$ $+$ $1$ and ends with $n$$^{2}$ and every group consists $2n-1$ numbers $15th$ group starts with 196 and ends with $225$ $sum$ = $\frac{No of terms}{2}$ * $[first$ $term$+$last$ $term]$ = $\frac{29}{2} * [(196+1) + 225]$ = $6119$ [...]

acknowledge-Ignored [...]