Preparation

GATE CSE Books – More Options

May 23, 2021 by Arjun Suresh 1 Comment

Best Books for GATE CSE with Relevant Chapters to Read Heads Up! These GATE CSE books are recommended for a good understanding of Computer Science subjects which is very essential for GATE. For each subject you may choose ANY ONE of the books and not all Please see Video Lectures for video lectures Algorithms & […]

6,550 total views, 26 views today

ISI PCB Previous Year Papers with Solution

May 18, 2021 by soujanya 2 Comments

Indian Statistical Institute(ISI) offers M Tech in Computer Science with the Admission Test Codes MMA/PCA and PCB. Each of these two tests MMA/PCA and PCB will have individual qualifying marks. Group A and Group B marks vary from Year to Year. Scope: This two-year programme is designed to provide a balance of theoretical and professional training […]

1,964 total views, 5 views today

ISI JRF Previous Year Papers with Solution

May 17, 2021 by soujanya 2 Comments

Indian Statistical Institute(ISI) offers Junior Research Fellowships (JRF) in Computer Science, Statistics, Mathematics, Quantitative Economics, and Quality, Reliability & Operations Research (QROR). The Exam Center Codes for JRF are JCSK, JCSB, JCSC which will conduct at […]

4,566 total views, 24 views today

ISI DCG Previous Year Papers with Solution

May 17, 2021 by soujanya Leave a Comment

Indian Statistical Institute(ISI) conduct the admission test for Postgraduate Diploma in Computer Applications(PGDCA) with the test code DCG. The Programme Code for PG Diploma in Computer Science is DCAG. ISI conducts one MCQ test for […]

3,660 total views, 16 views today

ISI MMA\PCA Previous Year Papers with Solution

May 17, 2021 by soujanya 3 Comments

Indian Statistical Institute(ISI) offers M Tech in Computer Science with the Admission Test CodesISI MMA\PCA and PCB. The Programme code for M Tech in Computer Science is MCSK. ISI conducts two Admission Tests on the same day for M.Tech(CS), one is MCQ, the test code for this is MMA, and another one is Descriptive Type, […]

5,022 total views, 12 views today

GATE Overflow
Aptitude Overflow

Answered: Postal Book Course

C) L and L’ cannot be predicted. because compliment of NFA is doesn’t means compliment of langugae. for eg. L = {starting with “a” over {a,b}} it L’ = { ϵ, b, ba,bba,baaa,baab …...} let M is NFA for L then M’ is not an NFA for L’ it may be sometimes in other example. [...]

Answered: Cyclic group

It can or cannot be. Because the order of group should be divisible by the order of element. [...]

Applied Test Series

Suppose that we are considering an enhancement that runs 10 times faster than the original machine but is usable only 40% of the time. What is the overall speedup gained by incorporating the enhancement. [...]

Answered: GATE CSE 2002 | Question: 15

Answered: GATE CSE 2002 | Question: 15

Please change natural join to simplest relational algebraic operations. [...]

Applied Test Series

Suppose you want to transfer a file from Hyderabad to Bangalore. The size of file is 90,000 bytes. The file will be transferred in 1,500-byte data packets, for which 40 bytes are taken up with headers. The size of acknowledgement packets is 40 bytes including header. Every packet is acknowledged. The communication is bidirectional and the bandwidth is 100 Mbps (megabits/sec) in each direction. Hosts can send and receive at the same time. The latency from Hyderabad to Bangalore is 5 ms, as is the latency in the opposite direction. Assume that time to process a packet is very small,… [...]

Answered: GATE Civil 2021 Set 2 | GA Question: 9

Answered: GATE Civil 2021 Set 2 | GA Question: 9

Similarly, do for another side Therefore, Area of shaded area = $2 * (\frac{ r^{2}}{4}(\pi – 2)) = \frac{ r^{2}}{2}(\pi – 2)$ Now, total area = $r^{2}$ Therefore, Probability = $ \frac{ \frac{ r^{2}}{2}(\pi – 2)}{r^{2}}$ = $ \frac{ 1}{2}(\pi – 2)$ = $\frac{ \pi}{2} – 1$ So, Ans is $C$ [...]

Answered: CAT2018-2: 98

Given that, DIAGRAM In drum$1,$ $A$ and $B$ are in the ratio of $18 : 7.$ So, the quantity of $A = \frac{18}{25}$ The quantity of $B = \frac{7}{25}$ In final mixture, $A$ and $B$ are in the ratio of $13 : 7.$ So, the quantity of $A = \frac{13}{20}$ The quantity of $B = \frac{7}{20}$ In drum$2,$ let us assume the proportion of $B$ with respect to the overall mixture is $x.$ So, $ \frac{ \frac{7}{25} \times 3 + x \times 4}{7} = \frac{7}{20}$ $\Rightarrow \frac{21}{25} + 4x = \frac{49}{20}$ $\Rightarrow 20 (21 + 100x) = 25… [...]

Answered: CAT2018-2: 83

Given that, Total mixture $ = 175 \; \text{ml} + 700 \; \text{ml} $ $ = 875 \; \text{ml} $ Gopal takes out $10\%$ of the mixture and substitutes it by water of the same amount. We know that, A container contains $\text{x} \; \text{units}$ of the liquid from which $\text{y} \; \text{units}$ are taken out and replaced by water. Again from this mixture $\text{y} \; \text{units}$ are taken out and replaced by water. If this process is repeated $\text{‘n’}$ times. Then, The liquid left in the container after $\frac{ \text{n}^{th} \text{operation}}{ \text{Original quantity of the liquid in the container}}… [...]

Answered: CAT2018-1: 95

Let the cost price per kg of type $A,$ and $B$ be $\text{Rs.} x$ and $\text{Rs.} y$ respectively. When, $A$ and $B$ are mixed in the ratio of $3:2,$ then the profit is $10\%,$ So, selling price $:$ $ \left( \frac{3x+2y}{5} \right) \times \frac{110}{100} = 40 $ $ \Rightarrow \left( \frac{3x+2y}{5} \right) \times \frac{11}{10} = 40 \quad \longrightarrow (1) $ When, $A$ and $B$ are mixed in the ratio of $2:3,$ then the profit is $5\%.$ So, selling price $:$ $ \left( \frac{2x+3y}{5} \right) \times \frac{105}{100} = 40 $ $ \Rightarrow \left( \frac{2x+3y}{5} \right) \times \frac{21}{20} = 40 \quad \longrightarrow… [...]

Answered: CAT2018-1: 85

Let the cost price of peanuts per kg be $\text{Rs}. x.$ Then, the cost price of walnuts per kg be $\text{Rs}. 3x.$ A wholesaler sold $8 \; \text{kg}$ of peanuts at a profit of $10\%.$ So, the cost price of $8 \; \text{kg}$ peanuts $ = \text{Rs}. 8x.$ Therefore, selling price of $8 \; \text{kg}$ peanuts $ = 8x \times \frac{110}{100} = \text{Rs.} \frac{88x}{10} $ And, he also sold $16 \; \text{kg}$ walnuts at a profit of $20 \%.$ So, the cost price of $16 \; \text{kg}$ walnuts $ = 16 \times 3x = \text{Rs.} 48x $ Therefore, selling price… [...]

Answered: CAT2018-2: 88

Answered: CAT2018-2: 88

Given that, points $A$ and $B$ are $150 \; \text{km}$ apart. Each car travel at a speed of $100 \; \text{km/hr}$ for the first $50 \; \text{km}.$ $ \boxed{\text{Time} = \frac{\text{Distance}}{\text{Speed}}} $ So, $ t_{1} = \frac{50}{100} $ $ \Rightarrow \boxed{t_{1} = \frac{1}{2} \; \text{hour}} $ And, each car travel at a speed of $ 50 \; \text{kmph}$ for the $50 \; \text{km}.$ So, $ t_{2} = \frac{50}{50} $ $ \Rightarrow \boxed{t_{2} = 1 \; \text{hour}} $ And, each travel at a speed of $25 \; \text{kmph}$ for the last $50 \; \text{km}. $ So, $t_{3} = \frac{50}{25} $ $… [...]

Answered: CAT2018-2: 71

Answered: CAT2018-2: 71

Given that, $A$ and $B$ are two points such that $B$ is $350 \; \text{km}$ of $A.$ Let $`x\text{’}$ and $`y\text{’}$ be the speed $(\text{in km/hr})$ of cars starting from both $A$ and $B$ respectively. Let us assume $\text{car 2}$ traveled $ d\;\text{km}$ and meet $\text{car 1},$ after $1 \; \text{hour}.$ $\boxed{\text{Speed} = \frac{\text{Distance}}{\text{Time}}}$ So, $ S_{\text{car 1}} = \frac{350-d}{1} $ $\Rightarrow \boxed{x = 350 – d} \quad \longrightarrow (1) $ And, $ S_{\text{car 2}} = \frac{d}{1} $ $ \Rightarrow \boxed {y = d} $ From the equation $(1),$ we get $ x = 350 – d $ $ \Rightarrow x = 350 – y… [...]

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