GATE CSE 2016 Students did Better?

a little bit precizely address is a comibation of no of pages +each page size(bitsrequired for no of page+pageoffset{bits required for each page size })   so in question given 16 bits VAS and 4k page means 4kpage size default bytes 4kb means 2^12 16-12=4bits for no of pages so given address is 16064 =0011 1110 1100 0000                                                   4 | 12 bits     0011 is 3 (3rd page)  implies 2nd frame 2 frames are converted into binary 0010 rest twelve bits are same since off set will be same  =>0010 1110 1100 0000=>11968 option D   [...]

BCNF is considered to be an improved 3NF because in 3NF we can have fds where a non key derives a key attribute however that is not the case with BCNF, we can for sure say that all LHS of fds will be key attributes. [...]

${\log 2 \over \log x} + { \log 3 \over \log x} + {\log 4 \over \log x} = 1 \to \log(x) = \log(4 \times 3 \times 2) \to x = 24.$ [...]

B [...]

9 [...]

Given information: - Dick is thrice as old as Tom. Let Tom's age be x. - Harry is twice as old as Dick. - Dick's age is 1 year less than the average age of all three. Step 1: Express Dick's age in terms of Tom's age (x). Dick's age = 3x Step 2: Express Harry's age in terms of Dick's age. Harry's age = 2 × Dick's age = 2 × 3x = 6x Step 3: Set up an equation for Dick's age being 1 year less than the average age of all three. Dick's age = (Tom's age [...]