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Numerical Aptitude Preparation Resources for GATE CSE

Numerical Aptitude is an important subject for GATE and it usually comes for around 5 marks in GATE. The syllabus is similar to general aptitude exams and the question standard follows that of GRE.                             

Numerical Aptitude Syllabus:

  • Data interpretation: data graphs (bar graphs, pie charts, and other graphs representing data), 2- and 3-dimensional plots, maps, and tables
  • Numerical computation and estimation: ratios, percentages, powers, exponents and logarithms, permutations and combinations, and series
  • Mensuration and geometry
  • Elementary statistics and probability

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GATE CSE Syllabus

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Arjun Suresh

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  • One of the best website which is provide nice guidance of GATE STUDENT SALUTE MAM.

    Can I Help u to send some material to make your site more useful to Student.

    “Thinking is the capital, Enterprise is the way, Hard Work is the solution”-Abdul Kalam

  • @arjunsuresh:disqus
    Can you list down all type of questions we should be solve (1-2 q each) that will be good idea.
    Also I want to revise School Maths, i have seen many questions requiring 10th Std Maths,like Area /Volume of cylinder, Circle, if some list of topics can be prepared it'll be great. Keeping GATE point of view !
    You can also guide how to solve this kind of questions !

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9 years ago

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Let us rename the Person relation into 3 different relations $\rho R(Person)$ $\rho S(Person)$ $\rho P(Person)$ $R1 \leftarrow \sigma R.city = S.city \wedge R.pid \neq S.pid (R \times S)$ $R2 \leftarrow \sigma R.city = P.city \wedge R.pid \neq P.pid (R1 \times P)$ $R3 \leftarrow \prod city(R2)$ Hence ,we need 3 tables and 2 cross products. [...]

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c [...]

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B [...]

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d [...]

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Given information: - Dick is thrice as old as Tom. Let Tom's age be x. - Harry is twice as old as Dick. - Dick's age is 1 year less than the average age of all three. Step 1: Express Dick's age in terms of Tom's age (x). Dick's age = 3x Step 2: Express Harry's age in terms of Dick's age. Harry's age = 2 × Dick's age = 2 × 3x = 6x Step 3: Set up an equation for Dick's age being 1 year less than the average age of all three. Dick's age = (Tom's age [...]