Categories: Books, Videos & Mock Tests

Mock Tests for GATE

Mock Tests are useful for GATE — but only after you know the concepts well. Never ever try to learn by giving the mock tests. The tests must be used to see how well you can apply the concepts you know, how you can understand and skip difficult questions, how to optimize time in answering a question etc. For good tests like previous year GATE papers, you can spend a considerable time analyzing and seeing which all topics lost your marks and then seeing how you can improve on them. Many of the below tests even if paid have a considerable amount of wrong questions and answers and so if you are giving them — beware. Personally, if I’m taking GATE I will just take the previous year GATE papers, some free tests and if I have enough time then the tests by Testbook. I have very poor opinion of the question standard of any other paid test series and doing wrong questions corrupt your knowledge and will only reduce your final marks. GATE stands for quality and not quantity — choose the tests wisely.

Site Remarks Free/Paid New Questions/ Prev questions Subject wise or Full Length
GATE Overflow Tests GO now provides tests for GATE and this includes exact previous year GATE, ISRO papers and also their subject wise version. A few subject wise custom tests are also provided under the category “GATE Overflow Tests”. Bikram Ballav has also provided 4+ full length exams similar to GATE level and also many custom subject wise tests under the category “Tests by Mentors”. Free Both Both
Virtual GATE Techtud provides a free forum to share, learn and contribute precise technical information. Especially useful for GATE aspirants, it provides short videos on all subjects of GATE and Q&A by high technical expertize. Some previous questions are here. Free Both Both
TestBook Numerous mock tests in various categories with a bank of thousands of questions. Developed and compiled by a team of 40+ toppers and experts of respective exams. Exam preparation without a price tag. No gimmicks. No ads. Some previous questions are here. Paid/Free Both Both
Geeksquiz GeeksforGeeks Free Both Both
Made Easy They spend a good amount of money for test series. Usual subjects are covered well in their tests. But some topics like COA and Decidability are usually bad. If you can know and skip such ones, this test series is fine. Some previous questions are here. Paid New questions Both
GateForum From their website- “A complete online assessment module for GATE Aspirants the Online TarGATE provides the students with the flexibility of giving the tests at home and getting the score and performance analysis sitting at home. GATE is completely online for All streams and hence we have the Online TarGATE with all the 77 tests completely online” Paid New Questions Both
Techpariksha Techpariksha Paid/Free Both Both
TIME From their website- “In a bid to prepare the student for the rigors of the actual exam, T.I.M.E. test series incorporates all the required changes in the exam and simulates the exam environment. Enroll with T.I.M.E. GATE test series and give yourself that extra edge over the other GATE aspirants.” Paid Both Both
ACE For GATE 2016, ACE Test series was horrible and there was a rumor that the questions were made by M.Tech. students studying in ACE Engineering College. Some previous questions are here. Paid New questions Both

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8 years ago

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Answered: Can

Sigma star means all strings containing input Let's assume input is a,b so Sigma star is (a+b)* it is regular so it should be dcfl also. So talking about its pda push any input in stack push it until the input string got completed once it will be completed and will be in final state as it's acceptable to epsilon also so initial is also final So dpda is possible with final state [...]

Answered: virtual address translation

a little bit precizely address is a comibation of no of pages +each page size(bitsrequired for no of page+pageoffset{bits required for each page size })   so in question given 16 bits VAS and 4k page means 4kpage size default bytes 4kb means 2^12 16-12=4bits for no of pages so given address is 16064 =0011 1110 1100 0000                                                   4 | 12 bits     0011 is 3 (3rd page)  implies 2nd frame 2 frames are converted into binary 0010 rest twelve bits are same since off set will be same  =>0010 1110 1100 0000=>11968 option D   [...]

Answered: Segmentation

segment abale has and segment no base address  limit0segment no baseaddesslimit02196001230014290100313275804195296any process virtual adress will have two parts segment no and limitthat limit should be less that  segment table limit for specific segmentphysicall address is equal to base address and limita) 0,430=>43010500 is not less than 100 so invalidd. 3,400=>400112 is not less than 96 so invalid [...]

Answered: BCNF

BCNF is considered to be an improved 3NF because in 3NF we can have fds where a non key derives a key attribute however that is not the case with BCNF, we can for sure say that all LHS of fds will be key attributes. [...]

Answered: GATE CSE 2024 | Set 2 | Question: 35

Let us rename the Person relation into 3 different relations $\rho R(Person)$ $\rho S(Person)$ $\rho P(Person)$ $R1 \leftarrow \sigma R.city = S.city \wedge R.pid \neq S.pid (R \times S)$ $R2 \leftarrow \sigma R.city = P.city \wedge R.pid \neq P.pid (R1 \times P)$ $R3 \leftarrow \prod city(R2)$ Hence ,we need 3 tables and 2 cross products. [...]

Answered: GATE ECE 2024 | GA Question: 4

${\log 2 \over \log x} + { \log 3 \over \log x} + {\log 4 \over \log x} = 1 \to \log(x) = \log(4 \times 3 \times 2) \to x = 24.$ [...]

Answered: CAT 2015 | Question: 31

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Answered: CAT 2023 Set-3 | Quantitative Aptitude | Question: 2

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Answered: CAT 2023 Set-3 | Quantitative Aptitude | Question: 3

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Answered: CAT 2023 Set-3 | Quantitative Aptitude | Question: 5

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Answered: CAT 2023 Set-3 | Quantitative Aptitude | Question: 1

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Answered: CAT 2020 Set-3 | Question: 52

Given information: - Dick is thrice as old as Tom. Let Tom's age be x. - Harry is twice as old as Dick. - Dick's age is 1 year less than the average age of all three. Step 1: Express Dick's age in terms of Tom's age (x). Dick's age = 3x Step 2: Express Harry's age in terms of Dick's age. Harry's age = 2 × Dick's age = 2 × 3x = 6x Step 3: Set up an equation for Dick's age being 1 year less than the average age of all three. Dick's age = (Tom's age [...]