2018

2018 Year Placement Statistics for CSE

June 10, 2018 by Arjun Suresh Leave a Comment

Placement Statistics for Year 2018 for Computer Science & Engineering

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GATE CSE 2018 Admission Responses

June 7, 2018 by Arjun Suresh Leave a Comment

Admission Responses for GATE 2018 Computer Science and Engineering branch given by GATE Overflow users. You can know what rank people got into which all Institutes.

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GATE CSE 2018 Result Responses

June 7, 2018 by Arjun Suresh Leave a Comment

GATE Computer Science 2018 Result Responses submitted to GATE Overflow

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GATE CSE 2020 Syllabus

October 24, 2015 by Arjun Suresh 4 Comments

Detailed syllabus for GATE CSE 2016 with changes and links to previous year questions

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GATE Overflow Book- Q/A (Only Previous GATE/TIFR/CMI/ISI)

October 23, 2015 by Arjun Suresh 32 Comments

GATE Overflow Question & Answer- subject wise – only previous GATE CS/IT papers.

246,327 total views, 27 views today

GATE Overflow
Aptitude Overflow

Answered: GATE2001-2.15

With n vertices no. of possible edges = n C 2 Each subset of these edges will be form a graph. No. of possible undirected graphs is 2(n C 2) ⇒ 2(n(n-1)/2) [...]

Answered: NIELIT 2017 OCT Scientific Assistant A (CS) - Section B: 30

A – SHOULD BE THE ANSWER. [...]

Answered: GATE2009-26

Hence (i) and (iv) are equal. Ans (D) [...]

Answered: NIELIT 2017 OCT Scientific Assistant A (IT) - Section B: 32

SNR=SNR=10^SNR dB/10 =10^3.0=1000 Max data rate =3000 * log2 ( 1 + 1000 ) = 30,000 bps [...]

Answered: NIELIT 2017 OCT Scientific Assistant A (IT) - Section B: 9

starvation in scheduling algorithm occurs when any process is favoured over other. since FCFS and RR doesnt favour any process therfore they are starvation free.in priority based scheduling more priority process gets favoured over low priority hence Ans: A [...]

Answered: Andrew S. Tanenbaum Edition 5th Exercise 4 Question 17 (Page No. 352)

The minimum Ethernet frame is 64 bytes, including both addresses in the Ethernet frame header, the type/length field, and the checksum. Since the header fields occupy 18 bytes and the packet is 60 bytes, the total frame size is 78 bytes, which exceeds the 64-byte minimum. Therefore, no padding is used. [...]

Answered: NIELIT 2017 OCT Scientific Assistant A - Section A: 54

Answer (B) 18 cost price of 45 limbs =50 RS Selling price of limbs =40 RS(20 % loss on Cost price) women purchase 45 limbs of RS 50 means 9 limbs of RS 10 Without profit she sell 18 limbs of 20RS with 20 % profit she sell 18 limbs of 24 Rs [...]

Answered: NIELIT 2017 DEC Scientist B - Section A: 43

Option D. scientists will never fully understand how DNA functions. [...]

Answered: NIELIT 2017 DEC Scientist B - Section A: 22

Option C. human labour has dignity and value. [...]

Answered: NIELIT 2017 DEC Scientist B - Section A: 24

Option A. Poo Zat Poo, Tim $\Rightarrow$ Eat Good Mangoes …...(1) Sim Poo Kit $\Rightarrow$ Purchase Good sweets ……..(2) From (1) and (2) we can clearly say that Poo $\Rightarrow$ Good [...]

Answered: NIELIT 2017 DEC Scientist B - Section A: 19

Option D. Monday Condition is “She lectures in the afternoon on exactly two consecutive calendar days.” And “On Friday, she neither lectures nor conducts quizzes.” So, she can lectures only on $\left.\begin{matrix} Sunday & Monday\\ Monday & Tuesday \end{matrix}\right\} or$ [...]

Answered: NIELIT 2017 DEC Scientist B - Section A: 18

Option A. Conduct a quiz in the morning and lecture in the afternoon. Condition 1 : Conduct a quiz in the morning Condition 2 : If she conducts quizzes on Sunday, she does not conduct a quiz on Monday. Condition 3 : On Friday, she neither lectures nor conducts quizzes. From the above conditions She can conducts quiz on $\left.\begin{matrix} Sunday & Tuesday & Thursday\\ Monday & Tuesday & Thursday \end{matrix}\right\} or$ So, She must Conduct a quiz in the morning [...]

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