2017

Schedule for GATE CSE 2017

April 25, 2016 by pooja palod 8 Comments

26,723 total views, 6 views today

Cut offs for Masters Admissions

June 7, 2015 by admin Leave a Comment

Cut offs for Masters admission via GATE for CSE. Also, includes CCMT cutoffs and requirement for Ph.D. admissions in various IITs/IISc. and some foreign universities.

87,912 total views, 13 views today

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If you are looking for Operating System Book for knowledge purpose and to clear GATE Exam then Galvin is sufficient. In Gate Exam Questions from the following topics are generally asked in GATE exam. (1) Process Concepts (2) CPU Scheduling Algorithms ( 2 Marks Every Year Asked) (3) Banker’s Algorithms (4) Memory Management Questions like Calculation of Average Access time, Page replacement algorithms based questions, Logical address and physical address based questions. (5) Questions based on semaphore or critical section (6) Disk Scheduling Problems You can read Operating System Tutorials article to know more about Operating System for GATE exam [...]

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Inverse relation for mother-in-law – either son-in-law or daughter-in-law. Option A is the only possible answer. [...]

Answered: NIELIT 2016 MAR Scientist D: 16

We have $(D\to E), (\neg E \to A), (\neg B \to \neg C), (F \to \neg H), (\neg A \to B) $ Now, we have $(D,C)$ inside the hideout. So, $E$ must also be inside (due to $D \to E),$ and $B$ must also be inside due to $([\neg B \to \neg C] \leftrightarrow [C \to B]).$ This eliminates options A, B and C. Correct answer: D. [...]

Answered: NIELIT 2019 Feb Scientist D - Section D: 26

Relative speed of the dog, $S_r = \dfrac{(2 \times 2m) – (3 \times 1m)}{t},$ where $t$ is the time for two leaps of the dog. $\implies S_r = 1m/t$ So, after every $2$ leaps, the dog covers $1m$ distance to the fox. So, to cover $30\;m$ dog will need to make $2 \times 30 = 60$ leaps which will be $2 \times 60 = 120m$. Correct option: D. [...]

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