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GATE CSE College Reviews for Masters

June 10, 2018 by Arjun Suresh Leave a Comment

Reviews for Computer Science & Engineering Course for Masters by GATE Overflow members.

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Answered: GATE CSE 2021 Set 1 | Question: 55

Same as https://gateoverflow.in/43515/gate-cse-2007-question-72 [...]

Answered: TIFR2010-A-2

Its 11 times, option B is correct [...]

Answered: GATE CSE 2017 Set 1 | Question: GA-5

Probablity= required outcomes / total outcomes No of ways to form k-digits with no 0, 5, 9 (with repetitions allowed) = 7^k Total no of ways to for k-digit number( with repetitions allowed)= 9.(10^k-1) hence probablity= 7^k / 9.(10^k-1) == 1.11(0.7^k) similar to option C [...]

Answered: GATE CSE 2018 | Question: GA-1

They- used for specifying 3rd person object eg, 1) They were surprised with gifts. Their- used to specify any object in relation with the 3rd person. eg- 1) Their cycle was repaired, 2) we eat ours and you eat theirs. [...]

Answered: GATE CSE 1988 | Question: 2xa

$\textsf{Turn around time} = \textsf{Waiting time}+\textsf{Burst time}$ Since, $\textsf{Burst time}$ is independent of the scheduling algorthm, to minimize the average turn around time, the OS scheduler has to minimize average the waiting time. This means resorting to $\textsf{Shortest Remaining Time First}$ scheduling which on the positive side gives the minimum average waiting time but on the negative side can cause long burst time processes to $\textsf{starve}.$ [...]

Answered: GATE CSE 1988 | Question: 2xb

“Waiting time” is one of the metric for deciding the schedule of processes. If the OS tries to minimize the average waiting time of the processes it’ll follow the $\textsf{Shortest Remaining Time First}$ algorithm which though reduces the average waiting time of processes can still cause a long burst time process to $\textsf{starve.}$ [...]

Answered: CAT1996-45

Adbs [...]

Answered: CAT2001-51

A-H, B-F, C-E, D-G [...]

Logical Sequence of words

Arrange the words given below in a meaningful sequence. 1. Puberty 2. Adulthood 3. Childhood 4. Infancy 5. Senescence 6. Adolescence 2, 4, 6, 3, 1, 5 4, 3, 1, 6, 2, 5 4, 3, 6, 2, 1, 5 5, 6, 2, 3, 4, 1 [...]

Logical Sequence of words

Arrange the words given below in a meaningful sequence. 1. District 2. Village 3. State 4. Town 5. City 2, 4, 1, 5, 3 2, 1, 4, 5, 3 5, 3, 2, 1, 4 2, 5, 3, 4, 1 [...]

Answered: NIELIT 2019 Feb Scientist C - Section A: 29

Each term in the word “STABILISE” is $+1$ to each term in the word “UVCDKNKUG”. $S+2=U$ $T+2=V$ $A+2=C$ $B+2=D$ $I+2=K$ $L+2=N$ $I+2=K$ $S+2=U$ $E+2=G$ In the same way,”ORGANISE” can we be written as: $O+2=Q$ $R+2=T$ $G+2=I$ $A+2=C$ $N+2=P$ $I+2=K$ $S+2=U$ $E+2=G$ so “QTICPKUG”, option $A$ is correct here. [...]

Answered: CAT2019-2: 98

Ans should be ($150$) For a regular polygon with $n$ sides, each internal angle is given by $(n-2)\times \frac{180^{\circ}}{n}$ $\therefore$ Given $\angle B=\frac{3}{2}\times \angle A$ $\Rightarrow$ $(b-2)\times \frac{180^{\circ}}{b}=\frac{3}{2}\times (a-2)\times \frac{180^{\circ}}{a}$ $\therefore$ $2a-2=3a-6$ $\Rightarrow$ $a=4$ (using b=2a condition) Hence, $b=2a=8$ . Polygon of $a+b=12$ sides will have an internal angle $=(12-2)\times \frac{180^{\circ}}{12}=150^{\circ}$ [...]

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