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$a_{1}=3a_{0}+2b_{0}=3+4=7$ Now, $a_{n}-b_{n}=3a_{n-1}-a_{n-1}$ $a_{n}-2a_{n-1}=b_{n}\ \ ...........

This can also be a approach to the solution.

Use AM>GM, $$\frac{x^2 + \pi^2}{2} \geq \pi x$$ $$\frac{x^2 + x^{2\pi}}{2} \geq xx^{\pi}$$ $$\fra

Here we can use a prefix sum algorithm like array a[0-n] and b[0-n] let n = 5 content of a = [1,0,0,

Option D is incorrect because If we consider n=2 than Process X will compute a[0] and a[1] both but

System by default use write with no allocation, if specified then solve using write with allocation.

a.disguise

b.3300

Nurse – Friday

S-Lawyer because Lawyer stays home on thrusday.

C B D E F A this is the arrangement as per the given data. So C. DA is answer.

C B D E F A So B faces F.

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