operating-system

Natural join is used to join two relations having any number of attributes. It is denoted by a symbol ( ⨝). It is the combination of projection and filtered cartesian product. Ref: https://stackoverflow.com/questions/14127306/relational-algebra-cartesian-product-vs-natural-join [...]

Answered: NIELIT 2016

In relational databases, a tuple is one record (one row). A single entry in a table is called a Tuple or Record or Row. Ref: https://web.csulb.edu/colleges/coe/cecs/dbdesign/dbdesign.php?page=tables.php [...]

Answered: I have a confusion as to which colleges to choose from the list below for Mtech in CSE. My rank is 1694, Gate Score is 578, Category- General:- DTU, BITS Goa/Hyd, NIT Allahabad, NIT Rourkela, NIT Calicut?

IMO NIT Rourkela [...]

Answered: TNPSC 2017

Option (a) outer join [...]

Answered: CIL

Option (b) projection [...]

Answered: HCU PHD 2019 May

Relational algebra has $6$ basic relational operation. Select $(\sigma )$ Project $(\pi )$ Union $(\cup )$ Set difference$(-)$ Cartisian product $(\times )$ Rename $(\rho )$ Other Operations like Divide $(/)$ can be derived using the basic 6 operators. So,Only option (D) has derived operator , So Correct answer is option (D). [...]

Answered: CAT 1996 | Question: 49

abcs [...]

Answered: CAT 2001 | Question: 52

AE BF CG DH [...]

Answered: CAT 2010 | Question: 33

AE BF CG DH [...]

Answered: NIELIT 2019 Feb Scientist C - Section A: 22

Inverse relation for mother-in-law – either son-in-law or daughter-in-law. Option A is the only possible answer. [...]

Answered: NIELIT 2016 MAR Scientist D: 16

We have $(D\to E), (\neg E \to A), (\neg B \to \neg C), (F \to \neg H), (\neg A \to B) $ Now, we have $(D,C)$ inside the hideout. So, $E$ must also be inside (due to $D \to E),$ and $B$ must also be inside due to $([\neg B \to \neg C] \leftrightarrow [C \to B]).$ This eliminates options A, B and C. Correct answer: D. [...]

Answered: NIELIT 2019 Feb Scientist D - Section D: 26

Relative speed of the dog, $S_r = \dfrac{(2 \times 2m) – (3 \times 1m)}{t},$ where $t$ is the time for two leaps of the dog. $\implies S_r = 1m/t$ So, after every $2$ leaps, the dog covers $1m$ distance to the fox. So, to cover $30\;m$ dog will need to make $2 \times 30 = 60$ leaps which will be $2 \times 60 = 120m$. Correct option: D. [...]

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