Books, Videos & Mock Tests

Best Books for GATE CSE with Relevant Chapters to Read

October 23, 2015 by Arjun Suresh 23 Comments

Best books for GATE preparation in Computer Science (CS & IT)

329,240 total views, 68 views today

Notes for GATE CSE

October 23, 2015 by Arjun Suresh 4 Comments

Notes for GATE CSE

110,838 total views, 11 views today

GATE Overflow Books (PDFs)

October 23, 2015 by Arjun Suresh 32 Comments

GATE Overflow Question & Answer- subject wise – only previous GATE CS/IT papers.

348,179 total views, 96 views today

Verbal Aptitude Preparation Resources for GATE CSE

July 29, 2015 by Arjun Suresh 4 Comments

Materials for GATE preparation in Verbal Ability

43,799 total views, 12 views today

Numerical Aptitude Preparation Resources for GATE CSE

July 29, 2015 by Arjun Suresh 6 Comments

Materials for GATE preparation in Numerical Ability

55,751 total views, 15 views today

GATE Overflow
Aptitude Overflow

Answered: BEGINNER FRIENDLY BOOK FOR ALGORITHMS ?

ykrishnay have you searched here: GATE CSE Resources GATE CSE Books – More Options Preparation [...]

Answered: Is "operating system three easy pieces" Book is enough for gate exam?

If you are looking for Operating System Book for knowledge purpose and to clear GATE Exam then Galvin is sufficient. In Gate Exam Questions from the following topics are generally asked in GATE exam. (1) Process Concepts (2) CPU Scheduling Algorithms ( 2 Marks Every Year Asked) (3) Banker’s Algorithms (4) Memory Management Questions like Calculation of Average Access time, Page replacement algorithms based questions, Logical address and physical address based questions. (5) Questions based on semaphore or critical section (6) Disk Scheduling Problems You can read Operating System Tutorials article to know more about Operating System for GATE exam [...]

Answered: State True or False: Classes of Grammar and respective automata

After discussion with deepak sir: First of all point 3 is wrongly framed. This are the points from Go classes telegram channel: “There exists a Bijection between Set of type 3 grammars and set of all regular expressions... YES. because both are countable infinite so have same cardinality as set of positive integers. But There exists a Bijection between Set of Turing machines and set of all regular expressions...? YES. Same reason. “ What is countably infinite? → when the set S has one to one correspondance with the natural number. So,similarly “Set of ALL Grammars and set of regular… [...]

Answered: Zeal Test Series 2019: Graph Theory - Graph Connectivity

All four options are correct. 1) consider $K_{2}$ 2) Example as given in the other answers 3) consider $K_{2}$ 4) consider $C_{6}$ [...]

Introduction to Graph Theory Exercises

Introduction to Graph Theory Exercises

This is the problem snapshot [...]

Anyone can send link to download quantative book of arun sarma?

Book for General Aptitude [...]

Answered: CAT 2001 | Question: 52

AE BF CG DH [...]

Answered: CAT 2010 | Question: 33

AE BF CG DH [...]

Answered: NIELIT 2019 Feb Scientist C - Section A: 22

Inverse relation for mother-in-law – either son-in-law or daughter-in-law. Option A is the only possible answer. [...]

Answered: NIELIT 2016 MAR Scientist D: 16

We have $(D\to E), (\neg E \to A), (\neg B \to \neg C), (F \to \neg H), (\neg A \to B) $ Now, we have $(D,C)$ inside the hideout. So, $E$ must also be inside (due to $D \to E),$ and $B$ must also be inside due to $([\neg B \to \neg C] \leftrightarrow [C \to B]).$ This eliminates options A, B and C. Correct answer: D. [...]

Answered: NIELIT 2019 Feb Scientist D - Section D: 26

Relative speed of the dog, $S_r = \dfrac{(2 \times 2m) – (3 \times 1m)}{t},$ where $t$ is the time for two leaps of the dog. $\implies S_r = 1m/t$ So, after every $2$ leaps, the dog covers $1m$ distance to the fox. So, to cover $30\;m$ dog will need to make $2 \times 30 = 60$ leaps which will be $2 \times 60 = 120m$. Correct option: D. [...]

Answered: What was the largest number of students in any year that went on to further study?

1. 3.585 2. 1.125 3. 5.can't say [...]

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